pqr is a 45 -45 90 triangle with the vertices q(6,4) and r(-6,_4) and m <p =90 p is in quadrant II
the answer is (-6,6). you can see it makes a right triangle if you graph it.
yes
P could be in quadrant II or in quad IV
namely P(-4,6) or P(4,-6)
To solve this question, we need to find the missing coordinate of vertex r in the given 45-45-90 triangle.
In a 45-45-90 triangle, the ratios of the sides are always 1:1:√2. This means that the lengths of the sides opposite the 45-degree angles are equal, and the length of the hypotenuse is √2 times the length of the other two sides.
From the given information, we know that vertex q is at (6,4) and vertex p is in quadrant II of the coordinate plane. Since p is in quadrant II, its y-coordinate must be positive. Therefore, the y-coordinate of vertex r is -4.
So the coordinates of vertex r are (-6, -4).