A given rectangle has an area of 20 square feet.what is the length for various widths?
I know a=L×W and I know 5×4 =20 . But not sure what I'm suppose to do
sounds like they want a table of widths and lengths
W = 1 ... L = 20
W = 2 ... L = 10
just make a table
To find the length for various widths of a given rectangle, you can rearrange the formula for the area of a rectangle, A = L × W, to solve for the length, L.
In this case, the area of the rectangle is given as 20 square feet. Let's consider different values for the width, W, and calculate the corresponding length, L.
Let's start with a width of 1 foot. Since the area is 20 square feet and the width is 1 foot, we can find the length by dividing the area by the width: L = A / W = 20 / 1 = 20 feet.
Now, for a width of 2 feet: L = A / W = 20 / 2 = 10 feet.
For a width of 3 feet: L = A / W = 20 / 3 = 6.67 feet (rounded to two decimal places).
For a width of 4 feet: L = A / W = 20 / 4 = 5 feet.
For a width of 5 feet: L = A / W = 20 / 5 = 4 feet.
So, using these calculations, we have lengths of 20 feet, 10 feet, 6.67 feet (rounded), 5 feet, and 4 feet for widths of 1, 2, 3, 4, and 5 feet respectively.
By substituting different values for the width into the equation A = L × W, you can find the corresponding length for each width.