Oleg ran 8.8 miles in 1 hour and 20 min. Assuming he continues at a constant rate ,how long will it take him to run any number of miles?
Half a mile ? 0 miles?
rate = distance / time = (44 / 5 mi) / (4 / 3 hr) = 33 / 5 = 6.6 mph
time = distance / rate
to find the time for any distance , just divide by 6.6 mph
1 hour and 20 minutes = 1 20/60 hours
= 1 1/3 hour
= 4/3 hour
since rate = distance/time
we have 8.8/(4/3) mph
= 8.8(3/4) mph
= 26.4/4 mph
= 6.6 mph
Scott just arrived at the same rate using different constants.
note that 8.8 = 88/10 = 44/5 <----- he used that in the numerator.
Now that we have the rate, just use
Time = distance/rate
to find the times for different distances
Thank you for taking your time to help me where I'm still confused is how do u determined what miles
To determine how long it will take Oleg to run any number of miles, we need to find his running rate, which is defined as the distance he runs divided by the time it takes him to run that distance.
We know that Oleg ran 8.8 miles in 1 hour and 20 minutes. First, we need to convert 1 hour and 20 minutes to a single unit of time (either hours or minutes). Since there are 60 minutes in an hour, we can convert 1 hour and 20 minutes to 1.33 hours (1 hour + 20 minutes/60 minutes).
Next, we can find Oleg's running rate by dividing the distance he ran by the time it took him:
Running rate = Distance / Time
Running rate = 8.8 miles / 1.33 hours
Now, we can use this running rate to calculate the time it would take Oleg to run any number of miles.
1) Half a mile:
To find the time it would take Oleg to run half a mile, we divide the distance (0.5 miles) by the running rate:
Time = Distance / Running rate
Time = 0.5 miles / (8.8 miles / 1.33 hours)
Time = 0.5 / (8.8 / 1.33)
Time ≈ 0.075 hours or approximately 4.5 minutes
Therefore, it would take Oleg approximately 4.5 minutes to run half a mile.
2) 0 miles:
Since Oleg is not running any distance (0 miles), the time it would take him is zero.
Therefore, it would take Oleg no time to run 0 miles.
Keep in mind that these calculations assume Oleg continues to run at a constant rate.