If diameter of iron pipe is 2.8cm
and 1mm thickness is melted and cylindrical rod of same length is formed find diameter of rod
This could be a really tough question (with some x values) if you don't know the length of the original iron pipe...
Do you?
If not you could work with the assumption of a 1 m pipe.
depending on whether the rod's inside or outside diameter is 28mm, the cross-section of iron area is either
π(28^2-27^2) = 55π cm^2
or
π(29^2-28^2) = 57π cm^2
So, the radius of the solid rod (πr^2) is either √55 or √57 cm
To find the diameter of the cylindrical rod formed after melting a 1mm thickness from an iron pipe with a diameter of 2.8cm, follow these steps:
1. First, calculate the original radius of the iron pipe.
- The diameter is given as 2.8cm, so divide it by 2 to get the radius.
- Radius = 2.8cm / 2 = 1.4cm
2. Next, subtract the thickness that was melted (1mm) from the original radius.
- Convert the thickness to centimeters by dividing it by 10.
- Adjust the original radius by subtracting the thickness: New radius = 1.4cm - (1mm / 10) cm.
3. Finally, double the new radius to find the diameter of the cylindrical rod.
- Diameter = 2 * New radius
So, by substituting the values into the equations, the diameter of the cylindrical rod can be calculated.