How much can be lifted using 2kg of effort using a jack screw with a 45cm handle and a 1/3 cm screw pitch?
Please show me the formula and how you broke down the equation
One turn=2PI*45cm
one turn move is up 1/3 cm
MA=2PI*45/(1/3)=6PI*45=90PI
lift=MA*effort=90*PI*effort.
Now your effort is not in force units. Kilograms is a unit of mass.
https://www.engineeringtoolbox.com/screw-jack-d_1308.html
kg is a mass measurement
... the weight (force) of 2 kg (on earth) is about 20 Newtons
the end of the 45 cm handle travels ... 2 * π * 47 cm ... for every 1/3 cm of lift
so the ideal (frictionless) max lift is ... (2 kg * 2 * π * 47 cm) / (1/3 cm)
To calculate how much can be lifted using 2kg of effort with a jack screw, we can use the concept of mechanical advantage. The formula for mechanical advantage is:
Mechanical Advantage = Length of Effort Arm / Length of Load Arm
In this case, the effort arm is the length of the handle (45cm), and the load arm is the distance traveled by the screw (pitch) for a single revolution (1/3 cm). Plugging the values into the formula:
Mechanical Advantage = 45cm / (1/3cm)
Now, let's simplify by converting 1/3 cm to decimal form:
Mechanical Advantage = 45cm / 0.33cm
Next, we divide 45cm by 0.33cm to find the mechanical advantage:
Mechanical Advantage ≈ 136.36
This means that the jack screw provides a mechanical advantage of approximately 136.36.
To determine how much weight can be lifted using 2kg of effort, we multiply the mechanical advantage by the effort applied:
Weight Lifted = Mechanical Advantage * Effort
Weight Lifted ≈ 136.36 * 2kg
Weight Lifted ≈ 272.72 kg
Therefore, using 2kg of effort with this jack screw, you can lift approximately 272.72 kg.