1. A fruit drops from the top of a tree 20m tall, the time it takes the fruit to reach the ground level is?
h = -1/2 g t^2 + ho = 0,
1/2 g t^2 = ho,
1/2 g t^2 = 20.
0.5*9.8t^2 = 20,
t = ?
A mango fruit to the ground from the top of its tree which is 5m high . how long does it takes to reach the ground
Gga
To find the time it takes for the fruit to reach the ground level, we can use the equation of motion:
s = ut + (1/2)at^2
Where:
s = distance (20m in this case)
u = initial velocity (0m/s since the fruit starts from rest)
a = acceleration due to gravity (-9.8m/s^2, assuming no air resistance)
t = time
Since the fruit falls vertically downward, we can take the initial velocity as zero and the equation simplifies to:
s = (1/2)at^2
Now we can rearrange the equation to solve for time (t):
t^2 = 2s/a
t = √(2s/a)
Plugging in the values:
t = √(2 * 20 / 9.8)
t ≈ 2.02 seconds
Therefore, it takes approximately 2.02 seconds for the fruit to reach the ground level.
free fall equation is ... h = -1/2 g t^2 + ho
h = 0 (ground level) , ho = drop height
plug in values and solve for t ... the positive value