The efficiency of a machine is 75%.If this machine raises a load of 150kg through a vertical height of 20cm,Calculate the workdone by labourer using the machine
(m * g * h) / efficiency
convert cm to m ... answer is in Joules
W = F * h = (150*9.8) * 0.20 = Work done by machine in Joules.
W/0.75 = Work done by laborer.
I really don't know the answer pls help with this question
To calculate the work done by the laborer using the machine, we need to first determine the input work and then use the efficiency formula.
1. First, calculate the input work using the formula:
Input Work = Output Work / Efficiency
The output work is the work done by the machine, which can be calculated as:
Output Work = Force × Distance
In this case, the force is equal to the weight of the load being raised, and the distance is the vertical height.
Weight = Mass × Gravity
where Mass is given as 150kg and Gravity is approximately 9.8 m/s^2.
Weight = 150 kg × 9.8 m/s^2
Distance = 20cm = 0.2m
Output Work = Weight × Distance
2. Once we have the output work, we can use the efficiency formula to calculate the input work:
Efficiency = Output Work / Input Work
3. Rearranging the formula, we have:
Input Work = Output Work / Efficiency
Now, let's calculate the work done by the laborer using the machine:
1. Calculate the weight:
Weight = 150 kg × 9.8 m/s^2 = 1470 N
2. Calculate the output work:
Output Work = Weight × Distance
Output Work = 1470 N × 0.2 m = 294 J
3. Calculate the input work:
Input Work = Output Work / Efficiency
Input Work = 294 J / 0.75 = 392 J
Therefore, the work done by the laborer using the machine is 392 Joules.