2.40g of copper (ii)tetraoxosulphate(iv) crystals are prepared from 0.45g of copper (ii) oxide.the copper (ii) tetraoxosulphate(vi) crystals contain 0.45g of water of crystallisation.what mass of crystals and what is the mass of water of crystallisation would be obtained from 1.2g of copper (ii) oxide.
The proper name for CuSO4 is copper(II) sulfate and that nutty name you've given it is out in left field somewhere.
You could go through the obvious stoichiometry steps but this isn't necessary in this problem if you recognize that this is a proportion.
0.45 g CuO produces 2.40 g CuSO4.xH2O with 0.45 g H2O so
1.20 g CuO produces.....x g CuSO4 with .....x g H2O
2.40 g CuSO4.xH2O x (1.20/0.45 = ? grams of the crystals.
0.45 g H2O x (1.20/0.45) = ? grams H2O in the crystals.
What is copper (ii) tetraoxsuiphater (vi)
To calculate the mass of copper (II) tetraoxosulphate (IV) crystals and the mass of water of crystallisation obtained from 1.2g of copper (II) oxide, we can use the concept of stoichiometry and the given information about the previous reaction.
Given:
Mass of copper (II) oxide used = 0.45g
Mass of copper (II) tetraoxosulphate (IV) crystals obtained = 2.40g
Mass of water of crystallisation = 0.45g
We can set up a proportion to find the ratio of copper (II) oxide to copper (II) tetraoxosulphate (IV) crystals using their masses:
0.45g CuO / 2.40g CuSO₄·xH₂O = 1.2g CuO / y grams CuSO₄·xH₂O
Cross-multiplying, we have:
0.45g CuO * y grams CuSO₄·xH₂O = 2.40g CuSO₄·xH₂O * 1.2g CuO
y grams CuSO₄·xH₂O = (2.40g CuSO₄·xH₂O * 1.2g CuO) / 0.45g CuO
Calculating the value of y gives us:
y = (2.40g * 1.2g) / 0.45g
y = 2.4g
Therefore, from 1.2g of copper (II) oxide, we would obtain 2.4g of copper (II) tetraoxosulphate (IV) crystals.
The mass of water of crystallisation remains the same, so it would still be 0.45g.
To solve this problem, we need to determine the mole-to-mole ratio between copper (II) oxide and copper (II) tetraoxosulphate (IV) crystals, as well as the mole-to-mole ratio between copper (II) tetraoxosulphate (VI) crystals and water of crystallization.
Here are the steps to find the mass of crystals and the mass of water of crystallization obtained from 1.2g of copper (II) oxide:
Step 1: Calculate the number of moles of copper (II) oxide
To calculate the number of moles of copper (II) oxide, we need to use its molar mass. The molar mass of copper (II) oxide (CuO) can be found by adding the atomic masses of copper (Cu) and oxygen (O).
Molar mass of CuO = (atomic mass of Cu) + (atomic mass of O)
= (63.55 g/mol) + (16.00 g/mol)
≈ 79.55 g/mol
Number of moles of CuO = mass of CuO / molar mass of CuO
= 1.2 g / 79.55 g/mol
≈ 0.01507 mol
Step 2: Calculate the number of moles of copper (II) tetraoxosulphate (IV) crystals
From the given information, we know that 0.45g of copper (II) oxide results in 2.40g of copper (II) tetraoxosulphate (IV) crystals. Using this information, we can calculate the molar mass of copper (II) tetraoxosulphate (IV) crystals.
Molar mass of copper (II) tetraoxosulphate (IV) crystals = (atomic mass of Cu) + 4 × (atomic mass of O) + (atomic mass of S)
= (63.55 g/mol) + 4 × (16.00 g/mol) + (32.07 g/mol)
≈ 159.83 g/mol
Using the molar mass of copper (II) tetraoxosulphate (IV) crystals, we can calculate the number of moles.
Number of moles of copper (II) tetraoxosulphate (IV) crystals = mass of copper (II) tetraoxosulphate (IV) crystals / molar mass of copper (II) tetraoxosulphate (IV) crystals
= 2.40 g / 159.83 g/mol
≈ 0.015021 mol
Step 3: Determine the moles of water of crystallization
The information given states that 0.45g of copper (II) oxide results in 0.45g of water of crystallization. Since the molar mass of water (H2O) is known, we can calculate the number of moles of water.
Molar mass of water (H2O) = (atomic mass of H) + 2 × (atomic mass of O)
= (1.01 g/mol) + 2 × (16.00 g/mol)
≈ 18.02 g/mol
Number of moles of water = mass of water / molar mass of water
= 0.45 g / 18.02 g/mol
≈ 0.02498 mol
Step 4: Calculate the mass of copper (II) tetraoxosulphate (IV) crystals
We can now use the mole-to-mole ratio between copper (II) oxide and copper (II) tetraoxosulphate (IV) crystals to find the mass of the crystals obtained from 1.2g of copper (II) oxide.
Mass of copper (II) tetraoxosulphate (IV) crystals = moles of copper (II) tetraoxosulphate (IV) crystals × molar mass of copper (II) tetraoxosulphate (IV) crystals
= 0.01507 mol × 159.83 g/mol
≈ 2.402 g
Step 5: Calculate the mass of water of crystallization
Using the mole-to-mole ratio between copper (II) tetraoxosulphate (VI) crystals and water of crystallization, we can find the mass of water of crystallization obtained from 1.2g of copper (II) oxide.
Mass of water of crystallization = moles of water × molar mass of water
= 0.02498 mol × 18.02 g/mol
≈ 0.450 g
Therefore, from 1.2g of copper (II) oxide, approximately 2.402g of copper (II) tetraoxosulphate (IV) crystals and approximately 0.450g of water of crystallization would be obtained.