Two trains travel in the same direction on parallel tracks. Train A starts out 50 kilometers ahead of Train B. Train A travels 90 kilometers per hour and Train B travel 100 kilometers per hour. In how many hours will the trains be in the same place?
Is the answer 5 hours?
yes,
easy way:
the faster train is gaining on the slower train at 10 km/h
it has to make up 50 km, so time = 50/10 or 5 hrs.
To determine the time it takes for the two trains to be in the same place, you need to find the time it takes for Train B to catch up to Train A.
First, let's calculate the relative speed of Train B with respect to Train A:
Relative Speed = Speed of Train B - Speed of Train A
Relative Speed = 100 km/h - 90 km/h
Relative Speed = 10 km/h
Now, we need to find the time it takes for Train B to cover the initial distance of 50 kilometers between the two trains. We can use the formula: Time = Distance / Speed.
Time = 50 km / 10 km/h
Time = 5 hours
Therefore, the two trains will be in the same place after 5 hours. So, your answer is correct.
To determine the amount of time it takes for the two trains to be in the same place, we need to consider the relative speed between the two trains.
Since Train B is traveling at a faster speed than Train A, it will eventually catch up to Train A.
The relative speed between the two trains is the difference between their speeds:
Relative speed = Speed of Train B - Speed of Train A.
Relative speed = 100 km/h - 90 km/h.
Relative speed = 10 km/h.
Since Train B is traveling 10 km/h faster than Train A, it will take Train B 5 hours to catch up to Train A.
Therefore, the correct answer is 5 hours.