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h t t p : / / w w w . j i s k h a . c o m / d i s p l a y . c g i ? i d = 1 2 6 7 4 1 7 1 8 8 I don't follow your work Reiny ¡î3sinx + cosx = 1 ¡î3cosx = 1cosx square both sides 3cos^2 x = 1  2cosx + cos^2 x 3(1sin^2 x) = 1
asked by Kate RESPONSE on March 1, 2010 
Trigonometry
4. Find the exact value for sin(x+y) if sinx=4/5 and cos y = 15/17. Angles x and y are in the fourth quadrant. 5. Find the exact value for cos 165degrees using the halfangle identity. 1. Solve: 2 cos^2x  3 cosx + 1 = 0 for 0
asked by Tiffany Enlow on April 10, 2009 
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Find the exact total of the areas bounded by the following functions: f(x) = sinx g(x) = cosx x = 0 x = 2pi I set my calculator to graph on the xaxis as a 2pi scale. The two functions appear to cross three times between x = 0 and
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Find all solutions of the equation in the interval [0,2pi) 2 cos^2 xcos x = 0 2cos^2 + cosx + 0 (x+1/2) (x+0/2) (2x+1) (x+0) 1/2,0 2Pi/3, 4pi/3, pi/2, 3pi/2 my teacher circled pi/2 and 3pi/2 What did I do wrong? I don't
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Really Stumped on this one, any help would be great! Thanks! Find the exact value of cos 2x using the double angle formula. cosx=−2/13 cosx=2/13 where π2
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Trigonometric Identities Prove: (tanx + secx 1)/(tanx  secx + 1)= tanx + secx My work so far: (sinx/cosx + 1/cosx + cosx/cosx)/(sinx/cos x  1/cosx + cosx/cosx)= tanx + cosx (just working on the left side) ((sinx + 1 
asked by Dave on January 2, 2007 
Trigonometry
a. Find the exact value of sin (theta  pi/6) b. Find the exact value of cos (theta  pi/4) c. For what numbers x, 2pi less than or equal to x less than or equal to 2pi does cos x = 1 d. What is the range of the cosine function?
asked by Cassie on April 9, 2011 
maths
(Sin^3xcos^3x)/(sinxcosx) – cosx/sqrt(1+cot^2x)2tanxcotx=1 where x∈(0,2pi) general value of x.
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Mathtrigonometry
Several questions from my homework, any are appreciated. Thanks! Solve: 1) sinxtanx=0 2) 3csc^2x=4 Find all solutions within (0,2pi) 3) cos4x(cosx1)=0 4) cos4x7cos2x=8 Use inverse functions where necessary to find solutions
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Trig
prove the identity (sinX)^6 +(cosX)^6= 1  3(sinX)^2 (cosX)^2 sinX^6= sinx^2 ^3 = (1cosX^2)^3 = (12CosX^2 + cos^4) (1cosX^2) then multiply that out 12CosX^2 + cos^4  cosX^2 + 2cos^4 cos^6 add that on the left to the cos^6,
asked by JungJung on December 8, 2006