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Write an equation of the line that passes through (-5,-1) and is parallel to the line y=-3x+6

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asked by AJ
  1. The only thing that will change is the constant, since the slope has to stay at -3
    so the new equation is y = -3x + b
    plug in your new point (-5,-1)
    -1 = -3(-5) + b
    -1 = 15 + b
    -16 = b

    so your new equation is y = -3x - 16

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    posted by Reiny
  2. your line has slope of -3
    So, now you have a point and a slope, so use the point-slope form of the new line:

    y+1 = -3(x+5)

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    posted by Steve

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