Maths
Write an equation of the line that passes through (5,1) and is parallel to the line y=3x+6
asked by
AJ

The only thing that will change is the constant, since the slope has to stay at 3
so the new equation is y = 3x + b
plug in your new point (5,1)
1 = 3(5) + b
1 = 15 + b
16 = b
so your new equation is y = 3x  16posted by Reiny

your line has slope of 3
So, now you have a point and a slope, so use the pointslope form of the new line:
y+1 = 3(x+5)posted by Steve
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