Pb(s) + KNO3(aq) ----> No reaction
HNO3(aq) + Sr(OH)2(aq) ----> H2O + Sr(NO3)2
NO3 being Nitrate, and (OH)2 meaning 2 Oxygen and 2 Hydrogen atoms in the second problem. The second two in the products of the second problem is a subscript for NO3.
Are these correct? Thank you!
answered above.
Yes, your understanding of the chemical formulas and reactions is mostly correct, but there are some slight errors.
In the first equation, the reaction between Pb(s) (solid lead) and KNO3(aq) (aqueous potassium nitrate) indeed does not occur. Therefore, the correct statement for this reaction would be: Pb(s) + KNO3(aq) ---> No reaction.
In the second equation, the reaction between HNO3(aq) (aqueous nitric acid) and Sr(OH)2(aq) (aqueous strontium hydroxide) is represented correctly. The products of this reaction are H2O (water) and Sr(NO3)2 (strontium nitrate). However, there's a small mistake in your description of the product. The subscript 2 in Sr(NO3)2 does not refer to NO3 but rather indicates that there are two NO3 groups bonded to each strontium ion. So, the balanced equation should be: HNO3(aq) + Sr(OH)2(aq) ---> H2O + Sr(NO3)2.
Keep in mind that the expressions (OH)2 and NO3 are not used to determine the number of oxygen and hydrogen atoms in a compound. Instead, they represent the hydroxide (OH-) and nitrate (NO3-) ions, respectively. These ions carry a charge and combine with other ions or compounds to form stable compounds.
I hope this clears up any confusion. If you have any more questions, feel free to ask!