Mass of earth is 5.97 x 10 kg and it's mean radius is 6.371 what's is value of g at earth surface
missing some units and exponents?
To calculate the value of g at the Earth's surface, you can use the formula for gravitational acceleration:
g = (G * M) / R^2
where:
g is the gravitational acceleration
G is the gravitational constant (approximately 6.67430 x 10^-11 m^3 kg^-1 s^-2)
M is the mass of the Earth
R is the radius of the Earth
Let's substitute the given values into the equation:
M = 5.97 × 10^24 kg
R = 6,371 km = 6.371 x 10^6 m
g = (6.67430 x 10^-11 m^3 kg^-1 s^-2 * 5.97 × 10^24 kg) / (6.371 x 10^6 m)^2
Now, let's simplify this equation step-by-step:
g = (6.67430 x 5.97 × 10^24) / (6.371 x 10^6)^2
g = 3.986004 x 10^14 / (4.060241 x 10^13)
g = 9.81 m/s^2
Therefore, the value of g (gravitational acceleration) at the Earth's surface is approximately 9.81 m/s^2.