Two force which is 10n are perpendicular to each other if one of them makes an angle of 60 then calculate the magnitude
two forces at 90 deg if one of them makes an angle of 60? Makes no sense to me.
Fr = 10 N. = The resultant of 2 forces ?(F1 and F2).
The angle between F1 and the resultant is 60o.
Cos60 = F1/10,
F1 = 5 N.
To calculate the magnitude of the force, we can use the Pythagorean theorem, as the two forces are perpendicular to each other.
Let's call the magnitude of the first force F1 and the magnitude of the second force F2. According to the problem, F1 and F2 are both 10 N.
Since the angle between the forces is given as 60 degrees, we can use trigonometry to find the magnitude of the resulting force.
Using the Pythagorean theorem, we have:
Resultant force squared = F1 squared + F2 squared
Let's substitute the given values:
Resultant force squared = 10 squared + 10 squared
Resultant force squared = 100 + 100
Resultant force squared = 200
To find the magnitude of the resultant force, we take the square root of both sides of the equation:
Resultant force = √200
Resultant force ≈ 14.14 N
Therefore, the magnitude of the resultant force is approximately 14.14 N.