A polar satellite is launched at 850km above earth. Find orbital speed.
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To find the orbital speed of a satellite, we can use the formula for orbital velocity:
V = sqrt(G * M / R)
Where:
V = Orbital speed (in meters per second)
G = Gravitational constant (approximately 6.67430 × 10^-11 N* m^2 / kg^2)
M = Mass of the Earth (approximately 5.972 × 10^24 kg)
R = Radius of the orbit from the center of the Earth (in meters)
In this case, the polar satellite is launched 850 km above the Earth's surface, but we need to convert it to meters by multiplying it by 1000 (since 1 km = 1000 m).
R = (850 km) * (1000 m / km) = 850,000 m
Now we can substitute the values into the formula to find the orbital speed:
V = sqrt((6.67430 × 10^-11 N* m^2 / kg^2) * (5.972 × 10^24 kg) / 850,000 m)
Calculating this, we get:
V ≈ sqrt(5893457000)
V ≈ 7674.8 m/s
Therefore, the orbital speed of the polar satellite launched at 850 km above Earth is approximately 7674.8 m/s.
To find the orbital speed of a satellite, you need to know the radius of its orbit.
The formula to calculate the orbital speed of a satellite is:
v = √(GM/r)
Where v is the orbital speed, G is the gravitational constant (approximately 6.674 × 10^-11 N m^2/kg^2), M is the mass of the Earth (approximately 5.972 × 10^24 kg), and r is the radius of the satellite's orbit.
In this case, the satellite is launched at a height of 850 km above Earth's surface. To calculate the radius of its orbit, you need to add the radius of the Earth to the altitude.
The average radius of the Earth is approximately 6,371 km.
Therefore, the radius of the satellite's orbit would be:
r = (6,371 + 850) km = 7,221 km = 7,221,000 meters
Plugging these values into the formula:
v = √((6.674 × 10^-11 N m^2/kg^2) × (5.972 × 10^24 kg) / (7,221,000 m))
Calculating this using a calculator or scientific notation:
v ≈ 7,674 m/s
So, the orbital speed of the polar satellite launched at 850 km above Earth is approximately 7,674 m/s.