Table: {y -4 31 4 68 12 }
x -2 3 0 4 2
Which of the following equations satisfies the five sets of numbers shown in the above table?
A. y = x^3 + 4
B. y = 2x^2 = 7
C. y = 2x
D. y = 3x + 1
E. y = 6x
i dont understand how you got this answer wwwwttttffffffff i hate math i should have just finished school when i had the chance to cheat off people wtfffrfffffffffffff
A.
y = x³ + 4
x = - 2 , y = ( - 2 )³ + 4 = - 8 + 4 = - 4
x = 3, y = 3³ + 4 = 27 + 4 = 31
x = 0, y = 0³ + 4 =0 + 4 = 4
x = 4, y = 4³ + 4 = 64 + 4 = 68
x = 2, y = 2³ + 4 = 8 + 4 = 12
BARBZ STAY IN SCHOOL!!
What’s answer on this one
Well, I have to say, some of these options are quite amusing! Let's see which equation satisfies the table:
Looking at the table, we can see that for each value of x, there is a corresponding value of y.
Let's check the options:
A. y = x^3 + 4:
For x = -2, we get y = (-2)^3 + 4 = -8 + 4 = -4. So this equation holds for the first pair, (-2, -4).
For x = 3, we get y = 3^3 + 4 = 27 + 4 = 31. So this equation holds for the second pair, (3, 31).
For x = 0, we get y = 0^3 + 4 = 0 + 4 = 4. So this equation holds for the third pair, (0, 4).
For x = 4, we get y = 4^3 + 4 = 64 + 4 = 68. So this equation holds for the fourth pair, (4, 68).
For x = 2, we get y = 2^3 + 4 = 8 + 4 = 12. So this equation holds for the fifth pair, (2, 12).
All the pairs satisfy this equation, so option A is correct!
Now, let's take a moment to appreciate option B. I mean, y = 2x^2 = 7? That's an equation on steroids - trying too hard to be wild and adding an unnecessary equal sign! But unfortunately, it doesn't satisfy any of the pairs.
So, the correct equation is A. y = x^3 + 4.
Hope that gave you a chuckle! But remember, math is no joke!
To determine which equation satisfies the given table of values, we can substitute the x-values into each equation and check if the resulting y-values match the ones provided in the table.
Let's go through each equation one by one:
A. y = x^3 + 4
Substituting the x-values in the table:
For x = -2, y = (-2)^3 + 4 = -8 + 4 = -4 (matching the y-value in the table)
For x = 3, y = 3^3 + 4 = 27 + 4 = 31 (matching the y-value in the table)
For x = 0, y = 0^3 + 4 = 0 + 4 = 4 (matching the y-value in the table)
For x = 4, y = 4^3 + 4 = 64 + 4 = 68 (matching the y-value in the table)
For x = 2, y = 2^3 + 4 = 8 + 4 = 12 (matching the y-value in the table)
B. y = 2x^2 + 7
Substituting the x-values in the table:
For x = -2, y = 2(-2)^2 + 7 = 2(4) + 7 = 8 + 7 = 15 (not matching the y-value in the table)
For x = 3, y = 2(3)^2 + 7 = 2(9) + 7 = 18 + 7 = 25 (not matching the y-value in the table)
For x = 0, y = 2(0)^2 + 7 = 2(0) + 7 = 0 + 7 = 7 (not matching the y-value in the table)
For x = 4, y = 2(4)^2 + 7 = 2(16) + 7 = 32 + 7 = 39 (not matching the y-value in the table)
For x = 2, y = 2(2)^2 + 7 = 2(4) + 7 = 8 + 7 = 15 (not matching the y-value in the table)
C. y = 2x
Substituting the x-values in the table:
For x = -2, y = 2(-2) = -4 (matching the y-value in the table)
For x = 3, y = 2(3) = 6 (not matching the y-value in the table)
For x = 0, y = 2(0) = 0 (not matching the y-value in the table)
For x = 4, y = 2(4) = 8 (not matching the y-value in the table)
For x = 2, y = 2(2) = 4 (matching the y-value in the table)
D. y = 3x + 1
Substituting the x-values in the table:
For x = -2, y = 3(-2) + 1 = -6 + 1 = -5 (not matching the y-value in the table)
For x = 3, y = 3(3) + 1 = 9 + 1 = 10 (not matching the y-value in the table)
For x = 0, y = 3(0) + 1 = 0 + 1 = 1 (not matching the y-value in the table)
For x = 4, y = 3(4) + 1 = 12 + 1 = 13 (not matching the y-value in the table)
For x = 2, y = 3(2) + 1 = 6 + 1 = 7 (matching the y-value in the table)
E. y = 6x
Substituting the x-values in the table:
For x = -2, y = 6(-2) = -12 (not matching the y-value in the table)
For x = 3, y = 6(3) = 18 (not matching the y-value in the table)
For x = 0, y = 6(0) = 0 (not matching the y-value in the table)
For x = 4, y = 6(4) = 24 (not matching the y-value in the table)
For x = 2, y = 6(2) = 12 (matching the y-value in the table)
From the analysis above, we can see that the equation y = x^3 + 4 satisfies all the given table values. Therefore, the correct answer is A.