What volume of distilled water should be added to 400cm3 of 2.0mol/dm 3 H2SO4 to obtain 0.20mol/dm3 of solution

cc1 x M1 = cc2 x M2

400 x 2.0 = cc2 x 0.2M

cc2 gives the TOTAL volume. Subtract 400 to find the volume that must be added.

the answer to the question

To determine the volume of distilled water needed to obtain a 0.20mol/dm3 solution, we can use the dilution formula:

C1V1 = C2V2

Where:
C1 = initial concentration (2.0mol/dm3)
V1 = initial volume (400cm3)
C2 = final concentration (0.20mol/dm3)
V2 = final volume (will be the sum of the initial volume and the volume of water added)

First, let's convert the initial volume from cm3 to dm3:
V1 = 400cm3 = 400/1000 dm3 = 0.4 dm3

Now let's rearrange the formula to solve for V2:
V2 = (C1 V1) / C2

Substituting the given values:
V2 = (2.0mol/dm3 * 0.4 dm3) / 0.20mol/dm3
V2 = 0.8 dm3

Therefore, you would need to add 0.8 dm3 (or 800 cm3) of distilled water to the 400 cm3 of 2.0mol/dm3 H2SO4 to obtain a 0.20mol/dm3 solution.