Carter left Town A at noon, driving toward Town B at an average speed of 50 mph. At 12:30 P.M., Max headed from Town B to Town A along the same road. At 3 P.M., they met each other along the way, and Carter realized that he had completed 60% of his journey.
A:How far was Town A from Town B?
B:At what speed was Max traveling?
( A ) 50 mph. x 3hr.=150 mi.
60%=150 mi.
1%=150 / 60
=15 / 6 =2.5 mi.
100%= 100 x 2.5
= 250 mi.
( B ) 100% - 60% = 40%
40% = 40 x 2.5 =100 mi.
Max traveled 100 mi.
1500 hr. - 1230 hr. = 2 1/2 hr.
100 mi. / 2 1/2 hr.
100 mi. / 5/2 hr.
*simplify 100 and 5 by 5*
20 x 2 = 40 mph.
I forgot something. It should read 1500 hr. - 1230 hr. = 230 = 2 1/2 sorry dannyboi!!
oh no prob.!! thank you btw lillyyy
A. r * t = 50 * 3 = 150 mi. = Distance Carter had traveled when they met.
0.6d = 150,
d = 250 mi. from town A to town B.
B. r * t = 250-150 = 100,
r * 2.5 = 100,
r = 40 mi/h.