If 35.00 mL of 0.25 M NaOH(aq) is mixed w/ 20.00 mL of 0.400 M HClO4(aq), the result solution would be:
So apparently the correct answer is BASIC, but I thought it would be neutral because the resulting solution would contain NaClO4 which has components of both a strong acid and a strong base. How could this be?
Moles base: .035*.25=.00875
moles acid: .020*.4=.00800
So you have excess base, and the resultant is basic solution
You are right IF you had some solid NaClO4 and placed it in a beaker of water. BUT you didn't have that. How many mols NaOH did you have? How many mols HClO4 did you have?
mols NaOH = M x L = 0.25 x 0.03500 = 0.00875
mols HClO4 = M x L = 0.400 x 0.0200 = 0.008
So you have enough NaOH to neutralize ALL of the HClO4 and have some NaOH left over which makes it basic.
So that means it would be neutral only if there was an equal amount of both NaOH and HClO4, correct?
That is correct.
To determine the nature of the resulting solution when NaOH(aq) and HClO4(aq) are mixed, we need to consider the reaction that occurs between these two substances. NaOH is a strong base, and HClO4 is a strong acid.
First, let's write the balanced chemical equation for the reaction between NaOH and HClO4:
NaOH(aq) + HClO4(aq) → NaClO4(aq) + H2O(l)
This reaction involves the neutralization of NaOH and HClO4 to form NaClO4 (sodium perchlorate) and water (H2O). The resulting solution will contain NaClO4 and water.
Now, let's analyze the nature of NaClO4. Sodium perchlorate, NaClO4, is a salt consisting of a metal cation (Na+) and a polyatomic anion (ClO4-). It is important to note that both Na+ and ClO4- ions are derived from strong electrolytes, NaOH, and HClO4, respectively.
When an ionic compound such as NaClO4 dissolves in water, it dissociates into its constituent ions. Both Na+ and ClO4- ions are completely ionized in water, making NaClO4 a strong electrolyte. However, neither the Na+ nor the ClO4- ions contribute significantly to the acidity or basicity of the resulting solution.
The nature of the resulting solution depends on the excess or deficit of H+ and OH- ions. In this case, the reaction between NaOH and HClO4 is a neutralization reaction, meaning that the number of moles of H+ ions from HClO4 will be equal to the number of moles of OH- ions from NaOH.
Therefore, the resulting solution will be neutral. Even though NaClO4 contains both components of a strong acid and a strong base, the reaction between NaOH and HClO4 ensures complete neutralization.
Hence, the correct answer is neutral, not basic.