How does .08/(.08+.92(2/23)^t/4) become 2/(2+23(2/23)^t/4)? I don't understand how .08 becomes 2 and .92 becomes 23.
Divide numerator and denominator by .04
They multiplied top and bottom by 25
.08/(.08+.92(2/23)^t/4)
= .08(25) / [(25) ((.08+.92(2/23)^t/4) ]
= 2 / (2 + 23(2/23)^t/4 )
notice Jerry's answer and mine are the same thing, since
k ÷ .04
= k x 1/.04
= k x 25
To understand how .08 becomes 2 and .92 becomes 23, let's break down the steps:
Step 1: Simplify the expression. Start with .08/(.08 + .92(2/23)^t/4).
Step 2: Simplify the numerator. The numerator is .08.
Step 3: Simplify the denominator. The denominator is .08 + .92(2/23)^t/4.
Step 4: Simplify the expression further. Divide both the numerator and the denominator by .08.
When you divide .08 by .08, you get 1. Therefore, the numerator .08 becomes 1.
Now, let's simplify the denominator:
.08 + .92(2/23)^t/4
Step 5: Distribute .92 into (2/23)^t/4.
Multiply .92 by (2/23)^t/4.
.92 * (2/23)^t/4 = (2/23)^t/4
Step 6: Simplify the denominator.
.08 + (2/23)^t/4
Step 7: Divide the whole expression by .08.
Divide both the numerator and the denominator by .08.
.08 + (2/23)^t/4 divided by .08 = (1/4) + (2/23)^t/4 divided by .08
When you divide .08 by .08, you get 1. Therefore, the first term .08 becomes 1.
Now, let's simplify the second term:
(2/23)^t/4 divided by .08
Step 8: Simplify the second term.
(2/23)^t/4 divided by .08 = 2(2/23)^t/4
In this step, we've just multiplied both the numerator and the denominator by 2.
Finally, we have:
1 + 2(2/23)^t/4
So, the expression .08/(.08 + .92(2/23)^t/4) simplifies to 2/(2 + 23(2/23)^t/4).