stats

Assume that​ women's heights are normally distributed with a mean given by mu equals 63.4 in​, and a standard deviation given by sigma equals 1.8 in. Complete parts a and b.
a. If 1 woman is randomly​ selected, find the probability that her height is between 62.7 in and 63.7 in.
The probability is approximately
nothing. ​(Round to four decimal places as​ needed.)

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asked by wendy
  1. Did you sketch your curve to see exactly what the question is asking? Then you have to find the z-scores from both ends and use your z-score table (and remember that it reads less than) so you have to do the right most bound - the left most bound.
    We will be happy to check your answer.

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    posted by MsPi_3.14159265
  2. the height range is from 7/18 s.d. below the mean to 3/18 above the mean

    a z-score table will show the portion of the population that lies in this range
    ... the portion is equivalent to the probability

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    posted by scott
  3. To do this type of question, typically you will need a set tables showing standard deviation values. These were traditionally found in the back of textbooks. Many books these days no longer have these, since much more accurate on-line applets will do the same thing.

    Here is one of the best: http://davidmlane.com/normal.html

    Make sure you have selected "Area from a value" (the default)
    Fill in your mean and SD, then click on 'between' , filling in these values

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    posted by Reiny

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