the density of gold bar is 19.0 g cm⁻³ when a hole of volume 1.0 cm³ is drilled into the bar , density of the gold bar will be

dr bob is correct, the density of gold is consant, it doesn't depend on the volume. In my reading, you were asking for the apparent density of the bar will a hole drilled it. Similar to a steel ship, the density of the ship depends quite a lot on what the volume contained within the steel. So you need to decide what the teacher is asking, IMO>

To calculate the density of the gold bar after drilling a hole, we need to consider the change in volume and mass.

Given:
Density of the gold bar = 19.0 g/cm³
Volume of the hole drilled = 1.0 cm³

We can start by finding the original mass of the gold bar. Density is defined as mass per unit volume, so we can rearrange the equation to calculate the mass:

Mass = Density * Volume

Mass = 19.0 g/cm³ * Original Volume

Now, to find the new volume of the gold bar after drilling the hole, we need to subtract the volume of the hole from the original volume:

New Volume = Original Volume - Volume of the Hole
New Volume = Original Volume - 1.0 cm³

Finally, we can calculate the new density by dividing the mass by the new volume:

New Density = Mass / New Volume

Substituting the values, we get:

New Density = (19.0 g/cm³ * Original Volume) / (Original Volume - 1.0 cm³)

Please note that the original volume needs to be known in order to calculate the new density accurately.

What was the original volume or mass of the gold bar?

The density of gold is the density of gold is the density of gold.