i have a graph that shows the motion of a cyclist.
as the velocity(m/s) goes up:1, 2, 3... the elapsed time(s) also increases, 2, 4, 6...
when the velocity is on 2 the time is on 2, when the velocity is on 3 the time is on 4...
the line that is drawn points upward
my question is, is the acceleration constant, decreasing, or increasing.. i know the formula for acceleration is is velocity/time.so i think the answer is decreasing???
If v increases with time, the bike is accelerating. In this case, the acceleration appears (from your description) to be constant since the change in velocity per time interval remains the same.
Hndi ko nga po alam kung ano ang sagot,nag hihingi po ako ng sagot sa aking tanong.
To determine the nature of the acceleration, we can analyze the relationship between velocity and time.
Given that the velocity increases linearly (1, 2, 3...) while the elapsed time also increases linearly (2, 4, 6...), we can conclude that the graph represents a constant acceleration.
Here's how we can confirm this:
1. Calculate the acceleration for two data points: (v₁, t₁) and (v₂, t₂).
- For the initial data point: v₁ = 1 m/s, t₁ = 2 s.
- For the subsequent data point: v₂ = 2 m/s, t₂ = 4 s.
2. Calculate the change in velocity (Δv) and change in time (Δt):
Δv = v₂ - v₁ = 2 m/s - 1 m/s = 1 m/s
Δt = t₂ - t₁ = 4 s - 2 s = 2 s
3. Finally, calculate the acceleration (a) using the formula a = Δv/Δt:
a = Δv/Δt = 1 m/s / 2 s = 0.5 m/s²
Since the resulting acceleration (0.5 m/s²) is constant, we can conclude that the acceleration in this scenario is constant.