Find a number such that when it is added to two-thirds of itself,the result is 70
x + (2/3)x = 70
x = 70 / (5/3)
x = 70 * (3/5)
x = 210 / 5 = 42
Let's assume the number is x. According to the given information:
x + (2/3)x = 70
To solve this equation, we first need to combine like terms:
(5/3)x = 70
Next, we can isolate x by multiplying both sides of the equation by the reciprocal of (5/3), which is (3/5):
x = 70 * (3/5)
Multiplying 70 by 3 and then dividing by 5 gives us:
x = 42
Therefore, the number we are looking for is 42.
To find the number, let's assume the number is x.
According to the problem, when the number is added to two-thirds of itself, the result is 70. Mathematically, this can be expressed as:
x + (2/3)x = 70
To solve this equation, we can simplify it by combining the x terms:
(1 + 2/3)x = 70
To combine the fractions, we need a common denominator, which is 3. Therefore, 1 in the fraction becomes 3/3:
(3/3 + 2/3)x = 70
Now, we can add the numerators:
(5/3)x = 70
To isolate x, we need to multiply both sides of the equation by the reciprocal of 5/3, which is 3/5:
x = (70) * (3/5)
x = 210/5
x = 42
Therefore, the number we're looking for is 42.