please show me how to solve these:
1. Simpson drives his car with an average velocity of 48.0 km/h to the east. How long will it take him to drive 144 km on a straight highway?
answer=3.00 h
2. How much time would Simpson save by increasing his average velocity to 56.0 km/h to the east?
answer=0.43 h
nevermind...the answer is .43HOURS..how did i get 2.57 hours...this question is really bothering me
distance=rate*time
time= distance/rate
so i got the first one. but for the second one i did: t=144/56 and i got 2.57..i guess that is in hours..how would i change that to seconds?
To solve these problems, we need to use the formula:
Time = Distance / Velocity
1. To find the time it will take Simpson to drive 144 km, we can substitute the distance (144 km) and the velocity (48.0 km/h) into the formula:
Time = 144 km / 48.0 km/h
Dividing 144 km by 48.0 km/h, we get:
Time = 3.00 h
Therefore, it will take Simpson 3.00 hours to drive 144 km.
2. To find the amount of time that Simpson would save by increasing his average velocity to 56.0 km/h, we need to compare the times taken at the two different velocities:
Time taken at 48.0 km/h = 144 km / 48.0 km/h = 3.00 h
Time taken at 56.0 km/h = 144 km / 56.0 km/h
Dividing 144 km by 56.0 km/h, we get:
Time taken at 56.0 km/h ≈ 2.57 h
To find the time saved, we subtract the time taken at 56.0 km/h from the time taken at 48.0 km/h:
Time saved = Time at 48.0 km/h - Time at 56.0 km/h
Time saved = 3.00 h - 2.57 h
Subtracting the two values, we get:
Time saved ≈ 0.43 h
Therefore, Simpson would save approximately 0.43 hours by increasing his average velocity to 56.0 km/h.