7. In the first race of the season, Carol swam her event in 5 minutes and 15 seconds. Her goal was to be able to swim the same distance in \frac{2}{3} 2 3 the time by the end of the season. If she reaches her goal, how long will it take her to swim the race at the end of the season?

Well, let me put on my swimming goggles and calculate this for you!

If Carol's goal is to swim the race in \frac{2}{3} of the time, we can find it by multiplying her initial time by \frac{2}{3}. So, 5 minutes and 15 seconds multiplied by \frac{2}{3} gives us:

(5 minutes + 15 seconds) * \frac{2}{3}

Let's begin by converting 5 minutes to seconds. Since there are 60 seconds in a minute:

5 minutes * 60 seconds = 300 seconds

Therefore, we have:

(300 seconds + 15 seconds) * \frac{2}{3}

Now, let's simplify the equation:

315 seconds * \frac{2}{3}

Multiplying the seconds gives us:

630 seconds * \frac{1}{3}

Finally, since there are 60 seconds in a minute, we divide by 60 to convert back to minutes:

630 seconds * \frac{1}{3} ÷ 60 = 10.5 seconds

So, if Carol reaches her goal, it will take her 10.5 seconds to swim the race at the end of the season!

To find out how long it will take Carol to swim the race at the end of the season, we need to find \frac{2}{3} of the time it took her in the first race.

Step 1: Convert the time to seconds:
5 minutes = 5 * 60 = 300 seconds
15 seconds

Step 2: Add the total number of seconds:
300 seconds + 15 seconds = 315 seconds

Step 3: Find \frac{2}{3} of 315 seconds:
\frac{2}{3} * 315 = 210 seconds

Therefore, it will take Carol 210 seconds to swim the race at the end of the season.

To find out how long it will take Carol to swim the race at the end of the season, we need to determine the time it would take for her to swim \frac{2}{3} (2/3) of her initial time.

Given that Carol's initial time is 5 minutes and 15 seconds, we need to find \frac{2}{3} (2/3) of 5 minutes and 15 seconds.

To find \frac{2}{3} (2/3) of a number, we can multiply the number by \frac{2}{3} (2/3).

5 minutes and 15 seconds can be represented as 5 + \frac{15}{60} (since there are 60 seconds in a minute).
So, 5 minutes and 15 seconds can be written as 5 + \frac{15}{60} = 5 + \frac{1}{4}.

Now, let's find \frac{2}{3} (2/3) of 5 + \frac{1}{4}.

\frac{2}{3} (2/3) × (5 + \frac{1}{4}) = (2/3) × (5 + \frac{1}{4}).

To multiply fractions, we multiply the numerators (top numbers) and the denominators (bottom numbers).

(2/3) × (5 + \frac{1}{4}) = \frac{2}{3} × \frac{20}{4} = \frac{40}{12} = \frac{10}{3}.

So, if Carol reaches her goal, it will take her \frac{10}{3} minutes or 3 minutes and \frac{1}{3} (1/3) minutes to swim the race at the end of the season.

5 minutes = 5*60 = 300 seconds.

300 seconds + 15 seconds = 315 seconds.
(2/3)*315 seconds = 210 seconds = 3 minutes and 30 seconds.