the vertical component of a force is200N . The force makes an angle of 30° with the horizontal. calculate the force

F sin 30 = 200 N

|F| = 400 N

F = 400 cos 30 i + 400 sin 30 j
or since you did not say what quadrant the force is in
F = 400 cos 30 i - 400 sin 30 j
or
F = -400 cos 30 i + 400 sin 30 j
or
F = -400 cos 30 i - 400 sin 30 j

I assume that amit means at MIT ?

To calculate the force, we can use the concept of vector components.

The vertical component of the force (Fv) is given as 200N. The force makes an angle of 30° with the horizontal, which means the angle between the force vector and the vertical axis is 90° - 30° = 60°.

Let's denote the magnitude of the force as F.
Using trigonometry, we can find the relationship between the vertical component and the total force:
Fv = F * sin(60°)

To find F, we can rearrange the equation:
F = Fv / sin(60°)

Now we can substitute the given value of Fv into the equation and calculate the force:
F = 200N / sin(60°)
F ≈ 229.13N

Therefore, the magnitude of the force is approximately 229.13N.