A is a solution of trioxonitate acid of an unknown concentration, B is a standard solution of sodium hydroxide containing 4.00g per dm3 of solution 25cm3 portion of solution B require an average of 24cm3 of solution A for complete neutralization. Write a balance equation for the reaction.calculate
A. Concentration of B in grame per dm3
B. Concentration of A in grame per dm3
C. Concentration in grame per dm3 of the trioxonitrate(v) acid in solution A
The correct name for trioxonitrate(v) acie is nitric acid or HNO3.
HNO3 + NaOH ==> NaNO3 + H2O
A.
(B) = 4.00 g/dm3
B.
M = molarity B = 4.00/molar mass NaOH = ?
M HNO3 x mL HNO3 = M NaOH x mL NaOH. You know M HNO3, mL HNO3 and M NaOH. Solve for M HNO3 in mols/dm3 and convert to grams/dm3.
C.
C is the same question as B.
Post your work if you get stuck.
To calculate the concentrations, we need to use the balanced chemical equation for the reaction. Let's first write the balanced equation:
HNO3 + NaOH → NaNO3 + H2O
From the equation, we can see that one mole of trioxonitrate acid reacts with one mole of sodium hydroxide to produce one mole of sodium nitrate and one mole of water.
A. Concentration of B in grams per dm3:
We know that 25 cm3 of solution B (sodium hydroxide) requires an average of 24 cm3 of solution A (trioxonitrate acid) for neutralization.
Using the volume and concentration relationship:
Concentration of B (in g/dm3) = concentration of B (in g/dm3) × volume of B (in dm3) / volume of B used (in dm3)
Since the solution B contains 4.00 g/dm3, we can substitute the values into the equation:
Concentration of B = 4.00 g/dm3 × 25 cm3 / 24 cm3 = 4.17 g/dm3
Therefore, the concentration of solution B is 4.17 g/dm3.
B. Concentration of A in grams per dm3:
Since we already know the volume relationship between solution B and solution A, we can use it to calculate the concentration of solution A.
Concentration of A = concentration of B × volume of B used (in dm3) / volume of A used (in dm3)
We know the concentration of B in grams per dm3 is 4.17 g/dm3, the volume of B used is 24 cm3, and the volume of A used is 25 cm3. Substituting these values, we can calculate the concentration of A:
Concentration of A = 4.17 g/dm3 × 24 cm3 / 25 cm3 = 4.00 g/dm3
Therefore, the concentration of solution A is 4.00 g/dm3.
C. Concentration in grams per dm3 of the trioxonitrate(V) acid in solution A:
Since we have already calculated the concentration in grams per dm3 of solution A in the previous step, the concentration of the trioxonitrate(V) acid in solution A will be the same. Therefore, the concentration in grams per dm3 of the trioxonitrate(V) acid in solution A is 4.00 g/dm3.