Jessica and her mother return from shopping with 14 packages. They park the car in the parking lot, which is 120 meters away from their house. Then they make several trips to bring the packages into their house. Jessica's mother can carry 3 packages at a time and Jessica can carry 2 packages at a time. Given that they always walk together and the least possible number of trips is made, find the total distance covered by both of them.

3 trips

360 meters

Gee Tam, I count about 9 posts from you this morning.

Jai and I have helped you with some of those.
But, it sure looks like you are just dumping your homework or your assignment on us.

Unless I see any effort on your part or any indication that you even tried these, expect no more replies from me.

Least no.of trips. 5

Total distance covered by them 1200 meters

To find the total distance covered by both Jessica and her mother, we need to find the number of trips they make to bring the 14 packages into their house.

Let's break down the problem step by step:

1. Determine the maximum number of trips they can make one at a time:
- Jessica's mother can carry 3 packages at a time, so she needs to make 14 / 3 = 4 trips.
- Jessica can carry 2 packages at a time, so she needs to make 14 / 2 = 7 trips.

2. Since they always walk together and the least possible number of trips is made, they can only go together and match the number of trips made by Jessica's mother.

3. Now, let's calculate the distance covered in one trip:
- The distance from the parking lot to their house is 120 meters.
- Since they make a round trip for each trip, the distance covered in one trip is 2 * 120 = 240 meters.

4. Finally, calculate the total distance covered by both of them:
- They make 4 trips, so the total distance covered by Jessica's mother is 4 * 240 = 960 meters.
- Jessica also makes 4 trips, so the total distance covered by Jessica is 4 * 240 = 960 meters.

Therefore, the total distance covered by both Jessica and her mother is 960 + 960 = 1920 meters.