If a skydiver has a forward velocity of 40 m/s, what is the forward velocity after one second?
What is the downward velocity after one second?
There is no horizontal force (ignoring air friction) so the horizontal velocity remains 40 m/s
In the vertical direction there will be acceleration down of about 9.81 m/s
If the original vertical speed was zero, after one second it will be 9.81 t = 9.81 m/s down
To determine the forward velocity after one second, we need to consider the acceleration due to gravity, which acts in the downward direction. Assuming there is no other force acting on the skydiver, like wind resistance, the forward velocity will remain constant at 40 m/s.
However, the downward velocity will change after one second due to the acceleration caused by gravity. The acceleration due to gravity is approximately 9.8 m/s². To find the change in velocity after one second, we can use the formula:
Change in velocity = Acceleration × Time
In this case, the change in velocity is equal to the acceleration due to gravity (9.8 m/s²) multiplied by the time (1 second). Therefore, the downward velocity after one second is 9.8 m/s.
To determine the forward velocity after one second, you need to know if there are any external forces acting on the skydiver that could affect the velocity. Assuming no external forces, the forward velocity will remain constant at 40 m/s during the one-second interval.
Now, let's calculate the downward velocity after one second. The downward velocity is affected by the force of gravity, which causes acceleration. The acceleration due to gravity is approximately 9.8 m/s².
Using the equation for constant acceleration:
Final velocity = Initial velocity + (acceleration × time)
The initial velocity of the skydiver in the downward direction is considered zero, as the problem does not provide any specific value.
So, the downward velocity after one second is:
Final velocity = 0 m/s + (9.8 m/s² × 1 s)
Final velocity = 9.8 m/s
Therefore, the downward velocity after one second is 9.8 m/s.