16. The equation models the height h in centimeters after t seconds of a weight attached to the end of a spring that has been stretched and then released.

h= 7 cos (π/3 t)

a. Solve the equation for t. (I'm pretty sure i've got this one solved)

T= 3 arccos(h/7)/π

b. Find the times at which the weight is first at a height of 1 cm, of 3 cm, and of 5 cm above the rest position. Round your answers to the nearest hundredth.

c. Find the times at which the weight is at a height of 1 cm, of 3 cm, and of 5 cm below the rest position for the second time. Round your answers to the nearest hundredth.

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  1. cos (π t / 3 ) = h/7
    (π/3)t =arc cos h/7
    t = (3/π) arc cos (h/7) agree
    but note changed the notation because for example π/3 t might mean pi / (3t)

    so for example if h = 1
    arc cos (1/7) = 1.42744876 radians
    t = (3/3.14)(1.43) seconds
    that should get you started

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  2. Im still confused. Do i plug in the centimeters somewhere? And what do i do to solve for the "above" and "below". I literally want to pull my hair out over this question so I would really appreciate if you could help me with that.

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  3. Im so sorry please excuse my reply. I read your reply again a few more times and i completely understand now. Thankyou so very much!

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