A pulley system shows is use to raise a load of 600N through 8m. If they efficency is 90%.calculate
a. Mechnical advantage
b. Workdone by the effort
c. Effort applied
I can not help you with A or C because I can not see how many parts you have in your tackle
for part B
0.9 W = 600 * 8
so
W = 600 * 8/ 0.90 Joules
To calculate the mechanical advantage, work done by the effort, and the effort applied in the pulley system, we can use the following formulas:
a. Mechanical Advantage (MA) = Load / Effort
b. Work Done by the Effort = Load * Distance
c. Effort Applied = Load / Efficiency
Given:
Load (L) = 600N
Distance (d) = 8m
Efficiency (E) = 90% (0.9)
Let's calculate each value step by step:
a. Mechanical Advantage (MA) = Load / Effort
Since we're given the load (L), we need to determine the effort (E) to find the mechanical advantage.
Effort (E) = Load / Efficiency = 600N / 0.9
Effort (E) = 666.67N
Mechanical Advantage (MA) = Load / Effort = 600N / 666.67N
Mechanical Advantage (MA) ≈ 0.9
b. Work Done by the Effort = Load * Distance
Work Done by the Effort = 600N * 8m
Work Done by the Effort = 4800Nm (or Joules)
c. Effort Applied = Load / Efficiency
Effort Applied = 600N / 0.9
Effort Applied = 666.67N
So, the answers are:
a. Mechanical Advantage (MA) ≈ 0.9
b. Work Done by the Effort = 4800Nm (or Joules)
c. Effort Applied = 666.67N