How do I find the intercept with y=√4x and y=x^2/4
I read that as:
Find the intersection of y=√4x and y=x^2/4
the x^2/4 = √(4x)
x^2 = 4√(4x)
square both sides:
x^4 = 16(4x) = 64x
x^4 - 64x = 0
x(x^3 - 64) = 0
x=0 or x = 4
if x = 0, y = 0
if x = 4 , y = √16 = 4
the two curves intersect at (0,0) and (4,4)
(notice the two points satisfy each of the equations)
check:
http://www.wolframalpha.com/input/?i=plot+y%3D%E2%88%9A4x+,+y%3Dx%5E2%2F4
since x≥0 from y = √4x, only look at the positive part of x