The pressure 15.0 meters under water is 248 kPa.
what is this pressure in bar? (how would you set this up)
what is the pressure in torr?
I believe the second one is set up like this: 248 kpa * (760 torr/ 101.325 kpa)= 1860.15.. Although, if the lowest sig fig is 3, then would my answer be 1860 or 186?
2.48*10^5 Pascals
1 atm is 1 bar = 10^5 Pascals
so
2.48 bar
1860.15 is about 1860
It is NOT about 186 !!!!!!
You could say it is 1.86 * 10^3 though
To convert the pressure from kPa to bar, you can use the conversion factor:
1 bar = 100 kPa
To set up the conversion, you can multiply the given pressure (248 kPa) by the conversion factor:
248 kPa * (1 bar/100 kPa)
The kPa will cancel out, leaving you with the pressure in bar.
For the second part of the question, to convert the pressure from kPa to torr, you can use the following conversion factors:
1 torr = 1 mmHg
1 atm = 760 torr
1 atm = 101.325 kPa
To set up the conversion, you can multiply the given pressure (248 kPa) by the conversion factors:
248 kPa * (1 atm/101.325 kPa) * (760 torr/1 atm)
Simplifying the units, you get:
248 * 760 torr / 101.325
This gives you the pressure in torr.
Regarding the significant figures, since the original value of 248 kPa has 3 significant figures, your final answer should also have 3 significant figures. Therefore, your answer should be 1860 torr, not 186.