2a+12y=-7 3a+2b=7
typo
You can not find values for a , y and b from two equations.
Either y is b or b is y.
Assuming your equations are:
2a + 12b = -7
3a + 2b = 7
multiply the 2nd equation by 6 to get
18a + 12b = 42
then subtract the 1st, that will eliminate the b, and go from there
To find the solution to the given system of equations, you can use the method of elimination or substitution. Let's go ahead and solve the system using the elimination method.
Step 1: Multiply the first equation by 3 and the second equation by 2 to make the coefficients of 'a' the same:
(3 * 2a) + (3 * 12y) = (3 * -7) --> 6a + 36y = -21
(2 * 3a) + (2 * 2b) = (2 * 7) --> 6a + 4b = 14
Step 2: Now, we can subtract the two equations to eliminate 'a':
(6a + 36y) - (6a + 4b) = -21 - 14
Simplifying the equation, we get:
36y - 4b = -35 --> 9y - b = -8.75 (by dividing both sides by 4)
So, one equation of the new system is 9y - b = -8.75.
Step 3: Now, let's rearrange the second equation of the original system to isolate 'a':
3a + 2b = 7 --> a = (7 - 2b)/3
So, the second equation of the new system is a = (7 - 2b)/3.
Therefore, the new system of equations is:
9y - b = -8.75 (equation 1)
a = (7 - 2b)/3 (equation 2)
Now you can solve this new system of equations using any method you prefer, such as substitution or elimination.