For the reaction N2(g)+o2(g)<-->2NO(g), you have the initial concentration [N2]=0.03 and [O2]=0.08 Keq for the reaction at this temperature is 5.7*10^-5. What are the equilibrium concentrations for N2, O2, and NO? Please help me with this!



http://www2.ucdsb.on.ca/tiss/stretton/CHEM2/equil5.htm

see problem 5 as an example

To solve this problem, we can use the concept of the equilibrium constant (Keq) and the stoichiometry of the reaction. Here's how you can approach it:

Step 1: Write down the given information and the balanced chemical equation:
N2(g) + O2(g) ⇌ 2NO(g)
Initial concentrations: [N2] = 0.03 M, [O2] = 0.08 M
Keq = 5.7 * 10^-5

Step 2: Define the changes in concentration based on the stoichiometry of the reaction. Let's say 'x' represents the change in concentration for both N2 and O2, and '2x' represents the change in concentration for NO.

Step 3: Write the equilibrium concentrations in terms of the initial concentrations and the changes in concentration:
[N2]eq = [N2]initial - x
[O2]eq = [O2]initial - x
[NO]eq = 2x

Step 4: Substitute these expressions into the expression for the equilibrium constant:
Keq = [NO]eq / ([N2]eq * [O2]eq)
5.7 * 10^-5 = (2x) / ([0.03 - x] * [0.08 - x])

Step 5: Solve for 'x':
Cross-multiply and rearrange the equation:
5.7 * 10^-5 * [0.03 - x] * [0.08 - x] = 2x

Expand and simplify the equation:
0.0001368 - 0.0095x + 0.0002x^2 = 2x

Rearrange the equation:
0.0002x^2 + 2.0095x - 0.0001368 = 0

This is a quadratic equation, which can be solved using the quadratic formula:
x = [-b ± √(b^2 - 4ac)] / (2a)

In this case, a = 0.0002, b = 2.0095, and c = -0.0001368. Substitute these values into the quadratic formula to find the value of 'x'.

Step 6: Substitute the value of 'x' into the equilibrium concentration expressions to calculate the equilibrium concentrations:
[N2]eq = [N2]initial - x
[O2]eq = [O2]initial - x
[NO]eq = 2x

Substitute the values of [N2]initial, [O2]initial, and 'x' to find the equilibrium concentrations.

For a numerical solution and to double-check your answer, you can refer to the example problem 5 on the provided link: http://www2.ucdsb.on.ca/tiss/stretton/CHEM2/equil5.htm