1.what is the shortest possible time in which a bacterium could travel a distance of 8.4 cm across a Petri dish at a constant speed of 3.5 mm/s.
the answer is 24s. how?
3.An athlete swims from the north end to the south end of a 50.0m pool in 20.0s and makes the return trip to the starting position in 22.0s.
a. What is the average velocity for the first half of the swim?
the answer is 2.50m/s to South
b. What is the average velocity for the second half of the swim?
the answer is 2.27m/s to North
c. What is the average velocity for the roundtrip?
the anser is 0.0 m/s
i have the answers, i need to know how to GET to the answers..step by step please.
convert cm to mm
8.4 cm times 10mm per cm equals 84mm
84mm divided by 3.5mm per s equals 24s
calculate average velocity for the first half of trip
50.0m divided by 20.0 equals 2.5m per s
calculate average velocity for 2nd half of trip
50.0 m divided by 22.0 s equals 2.27 m per s
average velocity is
change in distance divided by change in time
50m minus 50m divided by 22.0 s minus 20.0 s equals 0 m per s
I'm not certain about this one. But, I hope it helps.
Physics is HARD!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! }
JUST WAIT FOR IT
24s
can anyone answer these two questions??
For Q3 c; 0 m/s
How: Vavg=(50-50) / (20+22)
=0/42
=0 m/s
1. To find the time it takes for the bacterium to travel a distance of 8.4 cm at a constant speed of 3.5 mm/s, we can use the formula:
time = distance / speed
First, we need to convert the distance to millimeters, since the speed is given in millimeters per second:
8.4 cm = 8.4 * 10 mm = 84 mm
Now we can substitute the values into the formula:
time = 84 mm / 3.5 mm/s
Simplifying the expression:
time = 24 s
So the shortest possible time for the bacterium to travel 8.4 cm is 24 seconds.
2a. To find the average velocity for the first half of the swim, we need to calculate the displacement (change in position) of the athlete during that time. Since the athlete is swimming from the north end to the south end of the pool, the displacement is equal to the length of the pool, which is 50.0 meters, and the time taken is 20.0 seconds.
average velocity = displacement / time
Substituting the values into the formula:
average velocity = 50.0 m / 20.0 s
Calculating the average velocity:
average velocity = 2.50 m/s to South
2b. To find the average velocity for the second half of the swim, we use the same formula. The displacement will be the negative length of the pool (since the athlete is swimming back to the starting position) and the time taken is 22.0 seconds.
average velocity = displacement / time
Substituting the values:
average velocity = -50.0 m / 22.0 s
Calculating the average velocity:
average velocity = 2.27 m/s to North
2c. To find the average velocity for the round trip, we can calculate the total displacement, which is the sum of the displacements for the first and second halves of the swim. The total displacement is zero since the athlete returns to the starting position.
average velocity = total displacement / total time
The total time is the sum of the times for the first and second halves, which is 20.0 s + 22.0 s = 42.0 s.
average velocity = 0 m / 42.0 s
Calculating the average velocity:
average velocity = 0.0 m/s
So the average velocity for the round trip is 0.0 m/s.
Sure! I'll explain step-by-step how to get to the answers for each question.
1. To find the shortest possible time in which a bacterium could travel a distance of 8.4 cm across a Petri dish at a constant speed of 3.5 mm/s, you can use the formula Time = Distance / Speed.
Step 1: Convert the distance from centimeters to millimeters. Since 1 cm is equal to 10 mm, 8.4 cm is equal to 8.4 × 10 = 84 mm.
Step 2: Plug the values into the formula Time = Distance / Speed:
Time = 84 mm / 3.5 mm/s
Step 3: Simplify the expression:
Time = 24 seconds
Therefore, the shortest possible time for the bacterium to travel a distance of 8.4 cm is 24 seconds.
2. Let's break down each part of the question.
a. Average velocity for the first half of the swim:
Average velocity is calculated as Distance / Time.
Step 1: The distance for the first half of the swim is half of the total distance, which is 50.0 m / 2 = 25.0 m.
Step 2: Plug the values into the formula Average Velocity = Distance / Time:
Average Velocity = 25.0 m / 20.0 s
Step 3: Simplify the expression:
Average Velocity = 1.25 m/s to the South
Therefore, the average velocity for the first half of the swim is 1.25 m/s to the South.
b. Average velocity for the second half of the swim:
Since the athlete makes the return trip to the starting position, the average velocity for the second half will be the same in magnitude but opposite in direction.
Step 1: The distance for the second half of the swim is also 25.0 m.
Step 2: Plug the values into the formula Average Velocity = Distance / Time:
Average Velocity = 25.0 m / 22.0 s
Step 3: Simplify the expression:
Average Velocity = 1.14 m/s to the North
Therefore, the average velocity for the second half of the swim is 1.14 m/s to the North.
c. Average velocity for the round trip:
Since average velocity is defined as the total displacement divided by the total time, and the athlete returns to the starting position, the total displacement for the round trip is zero. Therefore, the average velocity for the round trip is 0.0 m/s.
I hope this step-by-step explanation helps you understand how to get to the answers!