# chemistry

We can determine the content (%) of calcium in milk through complexometric analysis by titration with EDTA. If we weigh 0.50 g of milk powder and titrate with EDTA 0.010 mol/L. What percentage of Ca2+does the milk if expended EDTA was 13.6 ml?

1. millimols Ca = mL EDTA x M EDTA = ?
grams Ca = mols Ca x atomic mas Ca = ?
% w/w = (grams Ca/mass sample)*100 = ?

posted by DrBob222
2. * Calculation of the quantity in moles of CA2 +:
V (EDTA) L * M (EDTA) = > 0.0136 * 0.010 = > 0.000136 moles CA2 +
* Calculation of the quantity in grams of Ca2 +:
Moles Ca2 + * atomic mass Ca 0.000136 * 40.078 = > 0.00545 g
Finally, percentage (%) of Ca2 +:
% = (mass g Ca2 +/sample) * 100
% = (0.00545/0.50) * 100
% = 0.0109 * 100
% = 1.09 g of CA2 +

posted by william

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