you roll a number cube. what are the odds in favor of rolling a 1 or a 5?thanks.
There are 6 sides of a cube.
You want one of 2 numbers to show up.
So it's 2/6 chance....or 1/3
Matt
I assume that you are talking about a die (Singular for "dice"), it has a total of 6 sides. Therefore, the probability of each number is 1/6.
For "either-or" probabilities, you need to add the probabilities of the individual events.
I hope this helps. Thanks for asking.
To determine the odds in favor of rolling a 1 or a 5, we need to calculate the probability of rolling a 1 and the probability of rolling a 5, and then add those probabilities together.
Since there are 6 sides on a number cube (or die), each side has an equal chance of landing face up, giving us a 1/6 probability for each number.
To calculate the probability of rolling a 1, we have 1 outcome that we want (rolling a 1) out of the 6 possible outcomes (rolling a 1, 2, 3, 4, 5, or 6). So the probability of rolling a 1 is 1/6.
To calculate the probability of rolling a 5, we again have 1 outcome that we want (rolling a 5) out of the 6 possible outcomes. So the probability of rolling a 5 is also 1/6.
To find the odds in favor of rolling a 1 or a 5, we add the probabilities together:
1/6 + 1/6 = 2/6 or simplified as 1/3
Therefore, the odds in favor of rolling a 1 or a 5 are 1 in 3.