you roll a number cube. what are the odds in favor of rolling a 1 or a 5?thanks.

There are 6 sides of a cube.
You want one of 2 numbers to show up.

So it's 2/6 chance....or 1/3

Matt

I assume that you are talking about a die (Singular for "dice"), it has a total of 6 sides. Therefore, the probability of each number is 1/6.

For "either-or" probabilities, you need to add the probabilities of the individual events.

I hope this helps. Thanks for asking.

To determine the odds in favor of rolling a 1 or a 5, we need to calculate the probability of rolling a 1 and the probability of rolling a 5, and then add those probabilities together.

Since there are 6 sides on a number cube (or die), each side has an equal chance of landing face up, giving us a 1/6 probability for each number.

To calculate the probability of rolling a 1, we have 1 outcome that we want (rolling a 1) out of the 6 possible outcomes (rolling a 1, 2, 3, 4, 5, or 6). So the probability of rolling a 1 is 1/6.

To calculate the probability of rolling a 5, we again have 1 outcome that we want (rolling a 5) out of the 6 possible outcomes. So the probability of rolling a 5 is also 1/6.

To find the odds in favor of rolling a 1 or a 5, we add the probabilities together:

1/6 + 1/6 = 2/6 or simplified as 1/3

Therefore, the odds in favor of rolling a 1 or a 5 are 1 in 3.