# Chemistry

What is the solubility of PbI2 in 0.4 M KI given the solubility constant of PbI2 is 7.1 x 10-9

a. 3.5 x 10-3 M

b. 1.2 x 10-3 M

c. 4.4 x 10-8 M

Ksp = 7.1 x 10-9
Ksp = x * (2 * 0.4)
(7.1 * 10-9)/.8 = x
8.8 x 10-9 = x ------ But this is not one of the answers. Please help. I think the answer may be C. Am I correct? Thanks

1. The problem gives KI as 0.4M and not 2*0.4 and that term is squared and not to the first power.. Two errors.

posted by DrBob222
2. 7.1 x 10^-9 = x * (0.4M)^2
(7.1 x 10^-9)/.16 = x
4.4 x 10^-8 = x
is this the correct way to solve this problem?

posted by Christine
3. yes

posted by DrBob222

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