Write the equation of a line perpendicular to 2y=3x+4 and passes through the point (7,-2).
Please help me i have no idea in this.
and please4 explain me how you did it. thanks.
The slope of the perpendular line must be -2/3. That is because the slope of your original line is 3/2. (The product of the slopes of perpendicular lines is always -1.)
Therefore the equation of the second line is of the form
y = (-2/3) x + C
Use the fact that y = -2 when x = 7 to compute the constant C.