A space vehicle travelling at a velocity of 6000km/h separates into two parts of mass 1200 kg and 300 kg. The two parts continue moving in the same direction with the lighter section moving at 6200km/h. Making use of the principle of conservation of momentum, determine the velocity of the heavier section after separation

6000*(1200+300)=300*6200+1200*V solve for V

To determine the velocity of the heavier section after separation, we can make use of the principle of conservation of momentum. According to this principle, the total momentum before the separation is equal to the total momentum after the separation.

The momentum of an object is given by the product of its mass and velocity. Mathematically, momentum (p) can be expressed as:

p = m * v

where p is the momentum, m is the mass of the object, and v is its velocity.

Let's start by calculating the momentum of the space vehicle before separation. We are given the velocity (v1) of the vehicle, and the masses (m1 and m2) of its two parts. The total momentum before separation can be expressed as:

p_total_initial = p1_initial + p2_initial

p_total_initial = (m1 * v1) + (m2 * v1)

Now, we need to use the information given to calculate the momentum of each part after separation. Let's assume the velocity of the heavier section after separation is v2.

The momentum of the lighter section after separation can be expressed as:

p1_final = m1 * v1_final

where the final velocity (v1_final) is given as 6200 km/h.

The momentum of the heavier section after separation can be expressed as:

p2_final = m2 * v2

Since the total momentum before separation is equal to the total momentum after separation, we can write:

p_total_initial = p1_final + p2_final

(m1 * v1) + (m2 * v1) = (m1 * v1_final) + (m2 * v2)

Substituting the given values:

(1200 kg * 6000 km/h) + (300 kg * 6000 km/h) = (1200 kg * 6200 km/h) + (300 kg * v2)

Now we can solve for v2:

(1200 * 6000) + (300 * 6000) = (1200 * 6200) + (300 * v2)

7200000 + 1800000 = 7440000 + 300v2

9000000 = 7440000 + 300v2

9000000 - 7440000 = 300v2

1560000 = 300v2

v2 = 1560000 / 300

v2 = 5200 km/h

Therefore, the velocity of the heavier section after separation is 5200 km/h.