Study the reaction.
A(s) + 2BC(aq) →AC2(aq) + B2(g)
ΔH = −92.0 kJ/mol
Which change would increase the rate of the forward reaction?
A. increasing the pressure
B. adding more of A(s)
C. adding water
D. decreasing the temperature
B?
Let me rewrite the equation.
A(s) + BC2(aq) ==>AC2(aq) + B2(g) + heat
Remember that solids do not, as long as a little of it is present, change concentration as more is added. I'm not sure that the correct answer is listed. It appears to me that the author of the problem meant to ask which change would increase the AMOUNT of the product at equilibrium (and not the rate) in which case d is the correct answer.
https://www.google.com/search?q=how+to+increase+rate+of+reaction&ie=utf-8&oe=utf-8&client=firefox-b-1
Yes, you are correct. Adding more of A(s) would increase the rate of the forward reaction. The presence of a solid reactant, A(s), typically increases the rate of a reaction because the surface area available for reaction increases, providing more opportunities for reactant molecules to collide and react. Therefore, adding more A(s) would increase the number of collisions and hence increase the rate of the reaction.
To determine which change would increase the rate of the forward reaction, we need to understand how different factors affect the rate of a reaction.
In this case, the reaction is represented as:
A(s) + 2BC(aq) → AC2(aq) + B2(g)
Possible changes that could increase the rate of the forward reaction are:
A. Increasing the pressure: The given reaction does not involve any gases in the reactants, so changing the pressure would not have a significant effect on the rate of the forward reaction. Therefore, this is not the correct answer.
B. Adding more of A(s): By increasing the concentration of the solid reactant A(s), the frequency of collision between A and BC would increase, leading to an increased rate of the forward reaction. Therefore, this is a potential correct answer.
C. Adding water: The addition of water does not directly affect the concentrations or the number of collisions of the reactants involved in the reaction. Therefore, this change is not likely to increase the rate of the forward reaction. Thus, this is not the correct answer.
D. Decreasing the temperature: Lowering the temperature generally slows down the rate of a chemical reaction. Since we want to increase the rate of the forward reaction, this is not the correct answer.
Based on the given options, it appears that the correct answer to increase the rate of the forward reaction will be option B, adding more of A(s) (increasing the concentration of A(s)).