A solution is prepared by dissolving 11gm glucose in 200 cm3 water at 30°c. What is the mass percentage of glucose in solution? The density of water 30°c is 0.996 glcm3?

Why did the glucose go to the party?

Because it wanted to be the life of the solution!

Now, let's calculate the mass percentage of glucose in the solution.

We know that the mass of the glucose is 11g and the mass of the water is (200 cm³) x (0.996 g/cm³) = 199.2g (approximately).

So, the total mass of the solution is 11g + 199.2g = 210.2g (approximately).

To calculate the mass percentage of glucose in the solution, we divide the mass of the glucose by the total mass of the solution and multiply by 100.

(11g / 210.2g) x 100 = 5.23% (approximately).

Therefore, the mass percentage of glucose in the solution is approximately 5.23%.

To find the mass percentage of glucose in the solution, we need to calculate the mass of glucose and the mass of the entire solution.

Step 1: Calculate the mass of the solution.
Given that the density of water at 30°C is 0.996 g/cm3, and the volume of the solution is 200 cm3, we can calculate the mass of the solution using the formula:
Mass of solution = Density × Volume
Mass of solution = 0.996 g/cm3 × 200 cm3
Mass of solution = 199.2 g

Step 2: Calculate the mass of glucose.
Given that the mass of glucose is 11 g, there is no need for any calculations.

Step 3: Calculate the mass percentage of glucose.
The mass percentage of glucose can be calculated using the formula:
Mass percentage of glucose = (Mass of glucose / Mass of solution) × 100
Mass percentage of glucose = (11 g / 199.2 g) × 100
Mass percentage of glucose = 5.52%

Therefore, the mass percentage of glucose in the solution is approximately 5.52%.

To find the mass percentage of glucose in the solution, you need to find the mass of glucose and the mass of the entire solution.

Step 1: Find the mass of the glucose.
Given that 11 grams of glucose is dissolved in the water.

Step 2: Find the mass of the solution.
Given that the density of water at 30°C is 0.996 g/cm3 and the volume of water is 200 cm3.
Mass of water = Volume of water × Density
Mass of water = 200 cm3 × 0.996 g/cm3

Step 3: Calculate the mass of the solution.
Mass of solution = mass of glucose + mass of water

Step 4: Calculate the mass percentage.
Mass percentage = (mass of glucose ÷ mass of solution) × 100

Now, let's calculate the values:

Step 1: Mass of the glucose = 11 grams

Step 2: Mass of water = 200 cm3 × 0.996 g/cm3
= 199.2 grams

Step 3: Mass of the solution = mass of glucose + mass of water
= 11 grams + 199.2 grams
= 210.2 grams

Step 4: Mass percentage = (11 grams ÷ 210.2 grams) × 100
≈ 5.23%

Therefore, the mass percentage of glucose in the solution is approximately 5.23%.

g H2O = volume x density. Substitute and solve for grams H2O.

Then % w/w = [(grams glucose)/(grams glucose + grams H2O)]*100 =