what will be the resistance of a metal wire of length 2m and area of cross section 1.55×10 power -6 m square is the resistivity is the metal be 2.8×10 power -8 ohm m
resistance=resitivity(length/area)=2.8e-8*(2/1.55e-6)=.036ohm
To calculate the resistance of a wire, we can use the formula:
Resistance (R) = (Resistivity * Length) / Area
Given:
Length (L) = 2m
Area of cross-section (A) = 1.55×10^(-6) m^2
Resistivity (ρ) = 2.8×10^(-8) Ωm
Using the formula, we can substitute the values:
R = (2.8×10^(-8) Ωm * 2m) / (1.55×10^(-6) m^2)
First, let's multiply the numbers:
R = (5.6×10^(-8) Ωm) / (1.55×10^(-6) m^2)
Next, divide the numbers:
R = 5.6×10^(-8) Ωm ÷ 1.55×10^(-6) m^2
To simplify scientific notation division, subtract the exponents:
R = 5.6 ÷ 1.55 × 10^(-8-(-6)) Ωm
R = 5.6 ÷ 1.55 × 10^(-2) Ω
Finally, simplify the arithmetic division:
R ≈ 3.61 × 10^(-1) Ω
Therefore, the resistance of the metal wire is approximately 0.361 Ω.