A large bar magnet (mass of 0.4 kg) exerts a 5 N force on a small bar magnet (mass of 0.1 kg) located 20 cm away. Calculate the force exerted by the small bar magnet on the large one.

forces are always in pairs: 5N

To calculate the force exerted by the small bar magnet on the large one, we can use Newton's third law of motion, which states that the force between two objects is equal in magnitude and opposite in direction.

Given:
Mass of the large bar magnet (m1) = 0.4 kg
Mass of the small bar magnet (m2) = 0.1 kg
Distance between the magnets (r) = 20 cm = 0.2 m
Force exerted by the large bar magnet (F1) = 5 N

According to Newton's third law:
F1 = F2

We can rearrange this equation to solve for F2 (the force exerted by the small bar magnet on the large one):

F2 = F1 = 5 N

Therefore, the force exerted by the small bar magnet on the large one is 5 N.