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Mathematics
How can 15 chocolates be divided among 6 members equally ??
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What is wrong with 2 and 1/2 each?
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Alice bought some chocolates. She saved 1/3 of the chocolates for her brother. She divided the rest of the chocolates equally
Top answer:
c = original number (2/3) c / 6 = x x/c = (2/3) / 6 = 2/18 = 1/9
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$5130 is to be divided equally among the members of a family group. Eight members of the family obtained knowledge of the loot
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See http://www.jiskha.com/display.cgi?id=1408443950
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$5130 is to be divided equally among the members of a family group. Eight members of the family obtained knowledge of the loot
Top answer:
This is more a riddle than math. In my opinion, it is hinged on the word "equally", which could mean
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Tom and Kathy together have 30 chocolates.Both of them lost 6 chocolates each,and the product of the number of chocolates now
Top answer:
t+k=30 (t-6)(k-6)=80 (t-6)((30-t)-6) = 80 (t-6)(24-t) = 80 24t-t^2-144+6t = 80 t^2 - 30t + 224 = 0
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The local reader’s club has a set of 64 hardback books and a set of 24 paperbacks. Each set can be divided equally among the
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It's 8. You needed to find the GCF of 24 and 64 (8) so that is the number
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The local reader’s club has a set of 36 hardback books and a set of 30 paperbacks. Each set can be divided equally among the
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what are all of the answers
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The local reader’s club has a set of 36 hardback books and a set of 30 paperbacks. Each set can be divided equally among the
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What is the greatest common factor of 30 and 36?
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Multiple Choice Question
There are 25 boxes of chocolates. Each box contains 56 chocolates. How many chocolates are there all
Top answer:
B. 1,400
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The local reader’s club has a set of 36 hardback books and a set of 30 paperbacks. Each set can be divided equally among the
Top answer:
GCD(30,36) = 6
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The local reader’s club has a set of 36 hardback books and a set of 30 paperbacks. Each set can be divided equally among the
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idk, uhm 6?
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