If a gas sample is 1/3 Neon and 2/3 krypton gas with a pressure of 120kPa, what is the pressure of each?
So what do you mean ? Is Ne 1/3 the mass 1/3 the pressure, 1/3 the mols?
Sorry I worded the question weirdly.
Q. If the gas sample is 1/3 Neon and 2/3 krypton with a total pressure of 120 kPa, what is the pressure of each gas?
You didn't change anything. You retyped the same question and you didn't answer my question.
According to the question,i it has to be 1/3 of the pressure
If that is the correct interpretation, then 1/3 x 120 = ? and 2/3 x 120 = ?
To find the pressure of each gas in the mixture, we need to use the Dalton's law of partial pressures. According to Dalton's law, the total pressure of a mixture of non-reacting gases is equal to the sum of the partial pressures of each gas.
In this case, the total pressure is given as 120 kPa. Given that the mixture contains 1/3 neon and 2/3 krypton gas, we can assign these fractions as the proportions of the partial pressures.
Let's calculate the partial pressure of neon:
Partial pressure of neon = Fraction of neon gas * Total pressure
Partial pressure of neon = 1/3 * 120 kPa
Partial pressure of neon = 40 kPa
Similarly, let's calculate the partial pressure of krypton:
Partial pressure of krypton = Fraction of krypton gas * Total pressure
Partial pressure of krypton = 2/3 * 120 kPa
Partial pressure of krypton = 80 kPa
Therefore, the pressure of neon gas is 40 kPa, and the pressure of krypton gas is 80 kPa.