What maszid hydrochloric acid is needed to decompose 50g of limestone?
assuming this particular limestone is purely CaCO3
CaCO3 + HCl
see
https://www.youtube.com/watch?v=PP3o4iQsy7U
CaCO3 mol mass = 40 + 12 + 3(16)
mols reacted = 50/(40+12+3*16)
calculate mols of HCl needed from balanced reaction (twice as many)
mol of HCl has mass 1+35.5
mass needed = mols of HCl needed *(36.5 grams/mol)
Answer is truly correct but more explaination I want. But thanku a lot
The answer is truly correct but more explaination I want
Thanku
the answer is absolutely correct but I need more explanation but thank you
To determine the amount of hydrochloric acid needed to decompose 50g of limestone, you need to know the balanced chemical equation for the reaction between hydrochloric acid (HCl) and limestone (calcium carbonate, CaCO3). The balanced equation is as follows:
CaCO3 + 2HCl -> CaCl2 + CO2 + H2O
From the equation, you can see that one mole of calcium carbonate reacts with two moles of hydrochloric acid to form one mole of calcium chloride, one mole of carbon dioxide, and one mole of water.
1. Calculate the molar mass of calcium carbonate (CaCO3):
- The atomic mass of calcium (Ca) is 40.08 g/mol.
- The atomic mass of carbon (C) is 12.01 g/mol.
- The atomic mass of oxygen (O) is 16.00 g/mol.
- Multiply the atomic masses by their respective subscripts and add them together:
(40.08 g/mol) + (12.01 g/mol) + (3 * 16.00 g/mol) = 100.09 g/mol.
2. Determine the number of moles of calcium carbonate in 50g:
- Divide the given mass by the molar mass:
50g / 100.09 g/mol ≈ 0.499 moles.
3. Using the balanced equation, you can see that for every one mole of calcium carbonate, you need two moles of hydrochloric acid. Therefore, you will need twice the number of moles of hydrochloric acid:
2 * 0.499 moles = 0.998 moles.
4. Finally, calculate the mass of hydrochloric acid needed:
- Multiply the number of moles by the molar mass of hydrochloric acid (HCl):
0.998 moles * (1 * 1.01 g/mol + 1 * 35.45 g/mol) ≈ 36.13 g.
Therefore, approximately 36.13 grams of hydrochloric acid is needed to decompose 50 grams of limestone.